newtons law please help?
An antique car has a mass of 585 kg with its riders. It starts from rest and travels to its top speed of 18.4 m/s over a distance of 60.89 m. It drives at this speed for 31 s. It is then allowed to roll to a stop. This takes 10.7 s.
alright i found the acceleration which is 2.78 M/s^2 but i need to know How much force acts on the car at the end to make it stop and What is the coefficient of friction between the car and the pavement? but finding the coefficiant is vital for me to understand… please help.
for finding the force i have been using F=ma but it is not working. i used 585 * 2.78 which is the acceleration but the computer is telling me im wrong.
I do not know how you got a= 2.78 m/s^2
The acceleration is change of velocity with respect to time
a=V/t= 18.4 /10.7 =1.72 m/s^2
You are correct F=ma
and the force of friction f=uN
u – coefficient of friction
N – normal force exerted by the car on the surface of motion.
Since N=mg we have
u mg= ma
u= a/g= 1.72 /9.81=0.175
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